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#ChemTeam: Gas Law Problems- Boyle s Law Answers

Gas Law Problems - Boyle's Law Answers: Part One

I tried to put the answers in the form of P1 V1 = P2 V2. They don't have to be in that order, except that the sub ones must be paired on one side of the equals sign and the sub twos must be paired on the other.

Some answers at the start are provided. Work the rest out. Show units on all values, not just the answer. Pay attention to sig figs.

1. (40.0 mm Hg) (12.3 liters) = (60.0 mm Hg) (x); x = 8.20 L, note three significant figures.

2. (1.00 atm) ( 3.60 liters) = (2.50 atm) (x); x = 1.44 L

3. ( 400.0 cu. ft) (1.00 atm) = (x) (3.00 cubic foot); x = 133 atm

4. (1.56 L) (1.00 atm) = (3.00 atm) (x); 0.520 L

5. (11.2 liters) (0.860 atm) = (x) (15.0 L); x = 0.642 atm

6. ( 745.0 mm Hg) (500.0 mL) = (760.0 mm Hg) (x)

7. (740.0 mm Hg) (350.0 mL) = (760.0 mm Hg) (x)

8. (63.0 atm) (338 L) = (1.00 atm) (x)

9. (166.0 mm Hg) (273.15 mL) = (760.0 mm Hg) (x)




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